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Home/ Questions/Q 7190049
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Editorial Team
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Editorial Team
Asked: May 28, 20262026-05-28T19:25:52+00:00 2026-05-28T19:25:52+00:00

Joining a list: >>> ”.join([ str(_) for _ in xrange(10) ]) ‘0123456789’ join must

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Joining a list:

>>> ''.join([ str(_) for _ in xrange(10) ])
'0123456789'

join must take an iterable.

Apparently, join‘s argument is [ str(_) for _ in xrange(10) ], and it’s a list comprehension.

Look at this:

>>>''.join( str(_) for _ in xrange(10) )
'0123456789'

Now, join‘s argument is just str(_) for _ in xrange(10), no [], but the result is the same.

Why? Does str(_) for _ in xrange(10) also produce a list or an iterable?

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  1. Editorial Team
    Editorial Team
    2026-05-28T19:25:52+00:00Added an answer on May 28, 2026 at 7:25 pm
    >>>''.join( str(_) for _ in xrange(10) )
    

    This is called a generator expression, and is explained in PEP 289.

    The main difference between generator expressions and list comprehensions is that the former don’t create the list in memory.

    Note that there’s a third way to write the expression:

    ''.join(map(str, xrange(10)))
    
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