Question

Jquery Ajax Call inserts new record on DB. File been called (php) needs to return two values, the contents of the insert and it’s id.

How should I send back these values (array, xml, echo) on php?

How will I separate these in the Jquery Ajax success (data)?

Currently the processing php file returns only one string being the inserted content with which I then update view. Need to return the record id so i can wire the element.

Please advice if this needs more clarification. Thank You

JQUERY

$.ajax({
                    type:'post',
                    url: 'posts_in.php',
                    data: $("#postentry").serialize(),
                    success:function(data){
                        var id='posts';
                        //split returned data here
                        $('<div></div>').attr('id',id).addClass('boxee').html(data).prependTo('#boxer');
                        $('#tittle_ent').val('').focus();
                    }

PHP

echo $value1,$value2;

print_r($arrayhere);

XML ?

Answer 1

Return a JSON string encoded with json_encode().

$php_array_result = array(1,2,3,4,5,6);

// Send the correct MIME header and echo out the JSON string
header("Content-type: application/json");
echo json_encode($php_array_result);
exit();

In your jQuery ajax call, add the dataType: "json" property.

$.ajax({
   type:'post',
   url: 'posts_in.php',
   dataType: "json",
   success: function(data) {
      console.dir(data);
   },
   // etc...