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Home/ Questions/Q 505853
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Editorial Team
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Editorial Team
Asked: May 13, 20262026-05-13T06:38:28+00:00 2026-05-13T06:38:28+00:00

jquery: $.post(process_login.php, {username : $(#username).val(), password : $(#password).val()}, function(data) { $(#login_results).fadeIn(slow).html(data); } ) html:

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jquery:

    $.post("process_login.php",
        {username : $("#username").val(), password : $("#password").val()},
        function(data) {
            $("#login_results").fadeIn("slow").html(data);
            }
        )

html:

<table>
    <tr><td id="login_results"></td></tr>
    <tr><td><input type="text" id="username" /></td></tr>
    <tr><td><input type="password" id="password" /></td></tr>
    <tr><td><input type="submit" id="login_submit" /></td></tr>
</table>

The data shows, but it doesn’t fade in. I have no idea why. =/. If you need any other details, let me know.

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  1. Editorial Team
    Editorial Team
    2026-05-13T06:38:28+00:00Added an answer on May 13, 2026 at 6:38 am

    probably because you have them in reverse order. you want

    $("#login_results").html(data).fadeIn("slow");
    

    otherwise you’re fading in something that doesn’t have any content yet.

    also, try putting what type of content is being returned by the post request.

    $.post("page", {params}, function(data){}, "html");
    

    after looking at the other answers, the more complete answer is to also make login_results invisible first:

    <td id='login_results' style='display:none'></td>
    
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