Question

jQuery(document).ready(function(){
    // Set the data text  
    var dataText = "
    { 
        name: 'John',
        time: '2pm' 
     }";  

    alert(dataText);
    // Create the AJAX request  
    $.ajax({  
        type: "POST",                    // Using the POST method  
        url: "/ajax/analytics/push",      // The file to call  
        data: dataText,                  // Our data to pass  
        success: function() {            // What to do on success  
             alert("Data Loaded: " + dataText);
        }  
    });  
});  
</script>   

hello im still learning ajax. how can we push a array of $_POST?

1.im trying to do something like

var dataText['name'] = 'Jhon';
var dataText['time] = '2pm';

then somehow turns it into

$_POST['name'] = 'Jhon';
$_POST['time'] = '2pm';

then send it to the url..

2.is there a way to debug this ? what im doing now is im writing

        # somehow doesnt work becouse its not auto refresh when the ajax sends a post
    var_dump($_POST);

        # ok heres how i debug it right now.
    ob_start();
    // write content
    $content = $_POST;
    ob_end_clean();
    file_put_contents('CACHE',$content);

in to a file, i hope there is a better solution for this..

Thankyou for looking in.
Adam Ramadhan

Answer 1

I’m not entirely sure what you’re doing. You seem to be building JSON manually (and not doing it correctly) and then passing that (in the JSON-serialised string form) to your file. You then seem to expect it to be parsed by PHP automatically.

It would be better to send it as key-value pairs. You can let jQuery do this for you if you pass in an object. This won’t look much different to your existing code:

var dataText = 
{ 
    name: 'John',
    time: '2pm' 
};  

Note that I have removed the double quotes. This is primarily because it is illegal to have a JS string covering more than one line without escaping the line breaks. It is also because you want the object to pass into your $.ajax call.

These should be available as $_POST['name'] and $_POST['time'] now.