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Home/ Questions/Q 9301833
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Editorial Team
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Editorial Team
Asked: June 18, 20262026-06-18T23:07:11+00:00 2026-06-18T23:07:11+00:00

jQuery’s clone function looks like this: .clone( [withDataAndEvents ] [, deepWithDataAndEvents ] ) withDataAndEvents

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jQuery’s clone function looks like this:

.clone( [withDataAndEvents ] [, deepWithDataAndEvents ] )

withDataAndEvents: A Boolean indicating
whether event handlers and data should be copied along with the
elements.

deepWithDataAndEvents: A Boolean indicating whether event handlers and data for all
children of the cloned element should be copied.

Both of these parameters affect data and events. Would it be possible to keep only the data, but not the events? Basically, my ideal clone function would look like this:

.idealClone( [withData] [, withEvents ] [, deepWithData ] [, deepWithEvents ] )

withData: A Boolean indicating
whether data should be copied along with the
elements.

withEvents: A Boolean indicating
whether event handlers should be copied along with the
elements.

deepWithData: A Boolean indicating whether data for all
children of the cloned element should be copied.

deepWithEvents: A Boolean indicating whether event handlers for all
children of the cloned element should be copied.

Is there any way to acheive this?

NB I’m working with 1.8.1, but answers for all version are welcome

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  1. Editorial Team
    Editorial Team
    2026-06-18T23:07:12+00:00Added an answer on June 18, 2026 at 11:07 pm

    You can easily extend the jQuery object with your ideal clone method, and use various combinations of data and off to keep only the things you want. Personally I think it’s easy enough to just do:

    // clones with data and events, then unbinds all events (bound with .on)
    $(element).clone(true).off();
    
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