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Home/ Questions/Q 367201
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Editorial Team
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Editorial Team
Asked: May 12, 20262026-05-12T13:42:19+00:00 2026-05-12T13:42:19+00:00

Just a little niggle about LINQ syntax. I’m flattening an IEnumerable<IEnumerable<T>> with SelectMany(x =>

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Just a little niggle about LINQ syntax. I’m flattening an IEnumerable<IEnumerable<T>> with SelectMany(x => x).

My problem is with the lambda expression x => x. It looks a bit ugly. Is there some static ‘identity function’ object that I can use instead of x => x? Something like SelectMany(IdentityFunction)?

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  1. Editorial Team
    Editorial Team
    2026-05-12T13:42:20+00:00Added an answer on May 12, 2026 at 1:42 pm

    Note: this answer was correct for C# 3, but at some point (C# 4? C# 5?) type inference improved so that the IdentityFunction method shown below can be used easily.


    No, there isn’t. It would have to be generic, to start with:

    public static Func<T, T> IdentityFunction<T>()
    {
        return x => x;
    }
    

    But then type inference wouldn’t work, so you’d have to do:

    SelectMany(Helpers.IdentityFunction<Foo>())
    

    which is a lot uglier than x => x.

    Another possibility is that you wrap this in an extension method:

    public static IEnumerable<T> Flatten<T>
        (this IEnumerable<IEnumerable<T>> source)
    {
        return source.SelectMany(x => x);
    }
    

    Unfortunately with generic variance the way it is, that may well fall foul of various cases in C# 3… it wouldn’t be applicable to List<List<string>> for example. You could make it more generic:

    public static IEnumerable<TElement> Flatten<TElement, TWrapper>
        (this IEnumerable<TWrapper> source) where TWrapper : IEnumerable<TElement>
    {
        return source.SelectMany(x => x);
    }
    

    But again, you’ve then got type inference problems, I suspect…

    EDIT: To respond to the comments… yes, C# 4 makes this easier. Or rather, it makes the first Flatten method more useful than it is in C# 3. Here’s an example which works in C# 4, but doesn’t work in C# 3 because the compiler can’t convert from List<List<string>> to IEnumerable<IEnumerable<string>>:

    using System;
    using System.Collections.Generic;
    using System.Linq;
    
    public static class Extensions
    {
        public static IEnumerable<T> Flatten<T>
            (this IEnumerable<IEnumerable<T>> source)
        {
            return source.SelectMany(x => x);
        }
    }
    
    class Test
    {
        static void Main()
        {
            List<List<string>> strings = new List<List<string>>
            {
                new List<string> { "x", "y", "z" },
                new List<string> { "0", "1", "2" }
            };
    
            foreach (string x in strings.Flatten())
            {
                Console.WriteLine(x);
            }
        }
    }
    
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