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Asked: 2026-06-13T17:53:22+00:00

Just a small question: I’m trying to make my code JSLint errorfree, but ran

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Just a small question:
I’m trying to make my code JSLint errorfree, but ran into this problem:

Unexpected ‘\d’. (in both of the regex’s)

hourduration = parseInt(activity.endTime.replace(":\d\d", ""), 10) - parseInt(activity.startTime.replace(":00", ""), 10);

minuteduration = (parseInt(activity.endTime.replace("(\d)?\d:", ""), 10) - parseInt(activity.startTime.replace(":00", ""), 10)) / 60;

What can I do to improve my regex so that jslint will validate it?

Thanks!

Solution:

hourduration = parseInt(activity.endTime.replace(/:\d\d/, ""), 10) - parseInt(activity.startTime.replace(":00", ""), 10);

minuteduration = (parseInt(activity.endTime.replace(/(\d)?\d:/, ""), 10) - parseInt(activity.startTime.replace(":00", ""), 10)) / 60;
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1 Answer

  1. Editorial Team

    JSLint wants you to use a RegExp object or a /regex/ ‘string’, not a normal string:

    // JSLint error
foo.match(':\d\d');
foo.match(RegExp(':\\d\\d'));

// no error
foo.match(/:\d\d/);
foo.match(new RegExp(':\\d\\d'));

    EDIT: All examples are valid, but the last 2 are the official way of working with regexes.

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