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Editorial Team
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Asked: 2026-05-16T01:47:32+00:00

Just starting using the Firebug console. I have a test script which I’ll post

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Just starting using the Firebug console. I have a test script which I’ll post below. I open up the Firebug console and type $(“p”); this returns null. Its my understanding it should return all my p elements ie p, p.foo, p, p#bar. A conflict maybe or am I just using the console incorrectly?

<!DOCTYPE html>
<html>
<head>
  <title>Testing jQuery</title>
</head>

<body>
    <p>Hello World!</p>
    <p class="foo">Another paragraph, but this one has a class.</p>
    <p><span>This is a span inside a paragraph.</span></p>
    <p id="bar">Paragraph with an id.
    <span class="foo">And this sentence is in a span.</span>
    </p>

    <script type="text/javascript" src="http://www.google.com/jsapi"></script>
    <script type="text/javascript"
        google.load("jquery", "1.4.2");
    </script>
</body>
</html>
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1 Answer

  1. Editorial Team

    You’re using the console correctly. Even if jQuery can’t find any results, it should return an empty object, not null.

    Could you console.log($); to see if jQuery is loaded?

    That should result in the jQuery function being returned:

    function ( selector, context ) {
    // The jQuery object is actually just the init constructor 'enhanced'
    return new jQuery.fn.init( selector, context );
}
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