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Home/ Questions/Q 1011901
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Editorial Team
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Editorial Team
Asked: May 16, 20262026-05-16T09:51:47+00:00 2026-05-16T09:51:47+00:00

KdPrint(( Unknown IoControlCode %#x\n, io_stack->Parameters.DeviceIoControl.IoControlCode )); It’s weird. What does sharp mean?

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KdPrint((
         "Unknown IoControlCode %#x\n",
                io_stack->Parameters.DeviceIoControl.IoControlCode
        ));

It’s weird. What does sharp mean?

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  1. Editorial Team
    Editorial Team
    2026-05-16T09:51:48+00:00Added an answer on May 16, 2026 at 9:51 am

    The printf documentation says:

    The character % is followed by zero or more of the following flags:

    # The value should be converted to an ‘‘alternate form’’.
    For o conversions, the first character
    of the output string is made zero (by
    prefixing a 0 if it was not zero
    already). For x and X conversions, a
    non-zero result
    has the string ‘0x’ (or ‘0X’ for X conversions) prepended to
    it. For a, A, e, E, f, F, g, and G
    conversions, the result will always
    contain a decimal point, even if no
    digits follow it (normally, a decimal
    point appears
    in the results of those conversions only if a digit follows).
    For g and G conversions, trailing
    zeros are not removed from the result
    as they would otherwise be. For other
    conversions, the result is undefined.

    MSDN docs on the flags are here.

    so for %#x the value is simply prefixed with 0x. Where %x would yield 34ab, %#x would yield 0x34ab.

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