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Home/ Questions/Q 7932567
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Editorial Team
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Editorial Team
Asked: June 3, 20262026-06-03T21:03:33+00:00 2026-06-03T21:03:33+00:00

<label for=dessert>What is your favourite dessert?*</label> <input type=text id=dessert onchange=checkForm()><br> <div id=dessertmsg> </div> <input

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<label for="dessert">What is your favourite dessert?*</label>
<input type="text" id="dessert" onchange="checkForm()"><br>
<div id="dessertmsg">  </div>

<input type="submit" value="Submit" id="subbutton" disabled> 

I want to show the button. To show the button, I want my validation to be true which is :

  function checkForm()

  {
  var dessert = document.getElementById("dessert").value;

  if(dessert == "cake"|| dessert == "cookie" || dessert == "icecream"){

When its true, i want the button to be enabled. I know i have to use disabled: False but how would i write the line of code for that? document.getElementById(what is the id for the disabled)??

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-03T21:03:34+00:00Added an answer on June 3, 2026 at 9:03 pm
    function checkForm() { 
        var button = document.getElementById("subbutton");
        var dessert = document.getElementById("dessert").value;
        if(dessert == "cake"|| dessert == "cookie" || dessert == "icecream") {
            button.disabled = undefined;
        }
        else {
            button.disabled = true;
        }
    }
    

    Example: http://jsfiddle.net/3NudE/ (with 3 nudes, woo!)

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