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Home/ Questions/Q 6879791
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Editorial Team
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Editorial Team
Asked: May 27, 20262026-05-27T04:53:28+00:00 2026-05-27T04:53:28+00:00

Let functionClass be a class derived from QObject . In the class constructor of

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Let functionClass be a class derived from QObject. In the class constructor of my QMainWindow class (which hasn’t started any other threads) I have the following code:

QThread workThread;
functionClass *functionClassObj = new functionClass;

cout << functionClassObj->thread()->currentThreadId() << endl; // prints 0x16c
functionClassObj->moveToThread( &workThread );
cout << functionClassObj->thread()->currentThreadId() << endl; // prints 0x16c

Why do the currentThreadId()functions print the same thing if I make a call to moveToThread()?

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  1. Editorial Team
    Editorial Team
    2026-05-27T04:53:29+00:00Added an answer on May 27, 2026 at 4:53 am

    currentThreadId() is a static member of QThread. This means that

    functionClassObj->currentThreadId();
    

    is equivalent to

    QThread::currentThreadId();
    

    which means that you’re going to get the same return value regardless of any object you use or don’t use to call the function.

    The function in question returns the id of the currently executing thread, and not the thread affinity of the object that you’re trying to call it on.

    If you want to get a reference to the thread object that the object has affinity for, use QObject::thread() instead.

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