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Home/ Questions/Q 6657397
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Editorial Team
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Editorial Team
Asked: May 26, 20262026-05-26T01:45:47+00:00 2026-05-26T01:45:47+00:00

let h = dict [(1, 2), (3, 4)] Console.WriteLine(h.Count) for i in h do

  • 0
let h = dict [(1, 2), (3, 4)]
Console.WriteLine(h.Count)
for i in h do
    Console.WriteLine(i)

gives me

1
[(1, 2), (3, 4)]

Two questions. Firstly, why does iterating over a dict give me back a sequence which only has 1 item, the dict itself? There is probably some logic behind this that will also affect other things I end up trying to iterate over. What does this mean for all the other Seq members exposed by dict (Any(), All(), Aggregate(), etc.)?

Secondly, is there a good way to iterate over and generally manipulate the key-value pairs in the dictionary, like in Python?

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  1. Editorial Team
    Editorial Team
    2026-05-26T01:45:48+00:00Added an answer on May 26, 2026 at 1:45 am

    You used a comma where you need a semicolon.

    [(1,2); (3,4)]
    

    Commas for tuples, semicolons for list elements. (The parens here are optional.)

    If you want to iterate over key-value pairs in the dictionary, you can use

    for KeyValue(k,v) in someDictionary do ...
    

    which uses the KeyValue active pattern.

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