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Home/ Questions/Q 8013131
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Editorial Team
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Editorial Team
Asked: June 4, 20262026-06-04T19:32:58+00:00 2026-06-04T19:32:58+00:00

Let it be std::list::iterator and std::list::reverse_iterator . Is reverse one derived from forward? And

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Let it be std::list::iterator and std::list::reverse_iterator. Is reverse one derived from forward? And if not then why there’re not reverse equivalents for member functions of list?

Thanks in advance.

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  1. Editorial Team
    Editorial Team
    2026-06-04T19:33:00+00:00Added an answer on June 4, 2026 at 7:33 pm

    Let it be std::list::iterator and std::list::reverse_iterator. Is reverse one derived from forward?

    Not necessarily, they may (and probably are in most implementations) different types. Iterators are copied around all the time, and this inheritance would cause slicing. Plus, all operations on iterator should be virtual to avoid inconsistencies, which would be inefficient. Thinking about it, it would make sense for the standard to even forbid inheritance as a possible implementation (and maybe it does, indirectly).

    Update: The standard provides a definition for std::reverse_iterator class template, and mandates that std::list::reverse_iterator is a specialization of such template. Inheritance is not a possible implementation.

    And if not then why there’re not reverse equivalents for member functions of list?

    Because you can call base() on a reverse_iterator to get the underlying regular iterator. The fundamental relation between a reverse_iterator and its corresponding iterator i is that &*(reverse_iterator(i)) == &*(i - 1).

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