Question

Let L = [1,2,3,4] be our list.

Then 1 in L is True. 2 in L is also True.

Is there a clean way to write (1,2) in L and have it come out true?

That is, given a list L and a test list T and the relation multi-in, if all members of T are in L, then T multi-in L is True, otherwise T multi-in L is False.

Of course I can write a multi-in function, but that seems ugly.

Answer 1

You want to treat (1,2) and L as sets:

set((1,2)).issubset(L)

or, nicer if you understand the notation:

set((1,2)) <= set(L)