Question

Let me first give some example table table which will make my question easier to understand.

Column1      Column2      Column3
Valuea       Value123     Value456
Valueax      Value123     Value456
Valueb       Value123     Value456
Valueb       Value123     Value456

select   Column1,
     Column2,
         Column3,
         count(*)
from     ColumnName
group by 
     Column1,
     Column2,
     Column3,
having   count(Count2+Count3) > 1 

I want to return ‘column1’, ‘column2’, ‘column3’ where column 2and3 will contain more than more duplicates but ‘column1’ must be different. So at present the above code would return:

Valueb       Value123     Value456 2

but i want it to return

Valuea       Value123     Value456
Valueax      Value123     Value456 

where column1 has different values but column2 and column3 values are the same.

Answer 1

You can’t group by concatenating. This will treat ‘xxx’ + ‘yyy’ the same as ‘x’ + ‘xxyyy’. How about getting

;WITH x AS 
(
   SELECT Column2, Column3 
   FROM dbo.table GROUP BY Column2, Column3
   HAVING COUNT(*) > 1
)
SELECT t.Column1, t.Column2, t.Column3
FROM x INNER JOIN dbo.table AS t
ON x.Column2 = t.Column2
AND x.Column3 = t.Column3
GROUP BY t.Column1, t.Column2, t.Column3
HAVING COUNT(*) = 1;

This assumes that none of these columns are NULLable.