Let me preface this by saying that perhaps there’s a better way to do

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Asked: May 20, 20262026-05-20T14:13:40+00:00 2026-05-20T14:13:40+00:00

Let me preface this by saying that perhaps there’s a better way to do

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Let me preface this by saying that perhaps there’s a better way to do this, and Razor is lighting the way. In any case, I have an HTML helper that acts as a repeater of sorts, but after an arbitrary number of repeats, it inserts an alternate template. Most obvious use? Tables that start a new row after x cells. The helper looks like this:

public static void SeriesSplitter<T>(this System.Web.Mvc.HtmlHelper htmlHelper, IEnumerable<T> items, int itemsBeforeSplit, Action<T> template, Action seriesSplitter)
{
    if (items == null)
        return;
    var i = 0;
    foreach (var item in items)
    {
        if (i != 0 && i % itemsBeforeSplit == 0)
            seriesSplitter();
        template(item);
        i++;
    }
}

And in a Webforms view, the usage looks like this:

<table>
    <tr>
    <% Html.SeriesSplitter(Model.Photos, 4, photo => { %>
            <td><img src="<%=ResolveUrl("~/Thumbnail.ashx?id=" + photo.ID)%>" alt="<%=Html.Encode(photo.Title)%>" /></td>
    <% }, () => { %></tr><tr><% }); %>
    </tr>
</table>

In this case, you’d have a table that renders four cells, then starts a new row by using the alternate template (the row start and end tags). The problem is that I can’t find a way to make this work in Razor. Using a lambda inside of a Razor view seems like a pretty weird construct.

What would you do?