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Home/ Questions/Q 8602127
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Editorial Team
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Editorial Team
Asked: June 12, 20262026-06-12T02:00:22+00:00 2026-06-12T02:00:22+00:00

Let me share some PHP code with you: $var1 = ”; $var2 = 0;

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Let me share some PHP code with you:

$var1 = '';

$var2 = 0;

echo '<pre>';
var_dump($var1 == $var2); //prints bool(true)
echo '</pre>';

echo '<pre>';
var_dump($var1 != $var2); //prints bool(false)
echo '</pre>';

echo '<pre>';
var_dump(!$var1 == $var2); //prints bool(false)
echo '</pre>';

echo '---<br />';

echo '<pre>';
var_dump($var1 === $var2); //prints bool(false)
echo '</pre>';

echo '<pre>';
var_dump($var1 !== $var2); //prints bool(true)
echo '</pre>';

echo '<pre>';
var_dump(!$var1 === $var2); //prints bool(false) .. WTFF????
echo '</pre>';

Question is… why does that last statement (! $var1 === $var2) NOT yield the same result as ($var !== $var2) ??? I mean, it’s what we would expect, no?

I used to use both ways interchangeably but now I only use !== although I still don’t know why the other form does not work…

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  1. Editorial Team
    Editorial Team
    2026-06-12T02:00:24+00:00Added an answer on June 12, 2026 at 2:00 am

    !$var1 is TRUE, $var2is 0.

    They are not equal, so the result is false.

    Maybe you were confused with !($var1 === $var2)

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