Question

Let’ say I have 2 sql queries. Table A contains,

ID
--
1
1
1
2
3
4

This query,

Select distinct ID1 FROM A

gives me,

ID
--
1
2
3
4

Second one

Select ID2 FROM B

which gives me,

ID2
--
8
21
33
43

How 2 get this record set?

ID1  ID2
---  ---
 1    8
 2    21
 3    33
 4    43

Answer 1

You did not specify what version of sql server but if you are using sql server 2008+, one way that you can do this is by adding the row_number() to each table and then joining on the row_number():

select a.id, b.id2
from
(
  select id, row_number() over(order by id) rn
  from a
) a
inner join
(
  select id2, row_number() over(order by id2) rn
  from b
) b
  on a.rn = b.rn

See SQL Fiddle with Demo

If you want to only use DISTINCT values, then you should be able to use:

select a.id, b.id2
from
(
  select id, row_number() over(order by id) rn
  from
  (
    select distinct id
    from a
  ) a
) a
inner join
(
  select id2, row_number() over(order by id2) rn
  from b
) b
  on a.rn = b.rn;

See SQL Fiddle with Demo

If you have a different number of rows in each table, then you might want to use a FULL OUTER JOIN:

select a.id, b.id2
from
(
  select id, row_number() over(order by id) rn
  from
  (
    select distinct id
    from a
  ) a
) a
full outer join
(
  select id2, row_number() over(order by id2) rn
  from b
) b
  on a.rn = b.rn;

See SQL Fiddle with Demo