Question

let say we have this pointer called text it print this thing in this format:

Date: Fri, 20 Apr 2012 11:42:05 GMT
Server: Apache/2.2.21 (Unix) mod_ssl/2.2.21 OpenSSL/0.9.8r DAV/2
PHP/5.3.6
X-Powered-By: PHP/5.3.6
Content-Length: 12
Connection: close
Content-Type: text/html
         <--- empty line

Start printing this

How can you start printing something when you detect a empty line in c or c++?

Answer 1

If you read line by line, just check the length of the line. If the length is zero, then you have an empty line.

If you have to check a memory buffer, then have a counter that is reset to zero on newline. If you reach a newline and the counter already is zero, then you have an empty line.

Edit: Some code how to do this with a memory buffer:

char *buffer = "Hello\nWorld\n\nFoo\n";
char *data_start = NULL;

char *line_beg, *p;
for (line_beg = p = buffer; *p; p++)
{
    if (*p == '\n')
    {
        if (line_beg == p)
        {
            /* Empty line */
            data_start = p + 1;
            break;
        }
        line_beg = p + 1;
    }
}

if (data_start != NULL)
    printf("Data: %s", data_start);