Question

Let this be the xml:

... some other parent elements here ...
<subject group="a">Economy</subject>
<subject group="b">Math</subject>
<subject group="a">Finance</subject>
<subject group="c">Arts</subject>
... some other elements here 

I would like to process and print a heading where group ‘a’ and ‘b’ is under one heading, and c is in another heading. ‘C’ is not a definite string, it can be ‘d’, ‘d’. I just want to seperate ‘a’ and ‘b’, from anything else. So an example output would be

Main Subjects (a and b)

• Economy Finance Math

Others

• Arts

Now, I have this code for the “Others” part:

<xsl:if test="not(subject/@group[. = 'a'] or subject/@group[. = 'b])">
                <h2>Others</h2> 
                <ul>
                    <xsl:for-each select="subject">      
                        <xsl:sort select="./@group"/>
                        <xsl:if test="@group!='a'and @type!='b'">
                            <xsl:apply-templates select="."/>
                        </xsl:if>
                    </xsl:for-each>
                </ul>
</xsl:if> 

This doesn’t work properly. I’ve tried without the not() and with !=

In short i just want to know if there is any element besides those of group a and b. If there is, print something, if there isn’t anything, don’t print out the heading “Others”.

Any help will be appreciated.

Answer 1

<?xml version="1.0" encoding="utf-8"?>
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
  <xsl:output method="html"/>
  <xsl:template match="/">
    <h2>Main Subjects</h2>
    <ul>
      <xsl:for-each select="//subject[@group/.='a' or @group/.='b']">
        <li>
          <xsl:value-of select="."/>
        </li>
      </xsl:for-each>
    </ul>
    <h2>Others</h2>
    <ul>
      <xsl:for-each select="//subject[not(@group/.='a' or @group/.='b')]">
        <li>
          <xsl:value-of select="."/>
        </li>
      </xsl:for-each>
    </ul>
  </xsl:template>
</xsl:stylesheet>

EDIT: @group/.='a' or @group ='a' both are fine,