Sign Up

Sign Up to our social questions and Answers Engine to ask questions, answer people’s questions, and connect with other people.

Have an account? Sign In

Have an account? Sign In Now

Sign In

Login to our social questions & Answers Engine to ask questions answer people’s questions & connect with other people.

Sign Up Here

Forgot Password?

Don't have account, Sign Up Here

Forgot Password

Lost your password? Please enter your email address. You will receive a link and will create a new password via email.

Have an account? Sign In Now

You must login to ask a question.

Forgot Password?

Need An Account, Sign Up Here

Please briefly explain why you feel this question should be reported.

Please briefly explain why you feel this answer should be reported.

Please briefly explain why you feel this user should be reported.

Sign InSign Up

The Archive Base

The Archive Base Logo The Archive Base Logo

The Archive Base Navigation

  • Home
  • SEARCH
  • About Us
  • Blog
  • Contact Us
Search
Ask A Question

Mobile menu

Close
Ask a Question
  • Home
  • Add group
  • Groups page
  • Feed
  • User Profile
  • Communities
  • Questions
    • New Questions
    • Trending Questions
    • Must read Questions
    • Hot Questions
  • Polls
  • Tags
  • Badges
  • Buy Points
  • Users
  • Help
  • Buy Theme
  • SEARCH
Home/ Questions/Q 352247
In Process

The Archive Base Latest Questions

Editorial Team
  • 0
Editorial Team
Asked: May 12, 20262026-05-12T11:43:09+00:00 2026-05-12T11:43:09+00:00

Let’s assume three models, standard joins: class Mailbox < ActiveRecord::Base has_many :addresses has_many :domains,

  • 0

Let’s assume three models, standard joins:

class Mailbox < ActiveRecord::Base
  has_many :addresses
  has_many :domains, :through => :addresses
end

class Address < ActiveRecord::Base
  belongs_to :mailbox
  belongs_to :domain
end

class Domain < ActiveRecord::Base
  has_many :addresses
  has_many :mailboxes, :through => :addresses
end

Now obviously, if for any given mailbox you want to know in which domains it has addresses, you have two possible ways to go:

m = Mailbox.first
# either: SELECT DISTINCT domains.id, domains.name FROM "domains" INNER JOIN 
#         "addresses" ON "domains".id = "addresses".domain_id WHERE 
#         (("addresses".mailbox_id = 1))
m.domains.all(:select => 'DISTINCT domains.id, domains.name')
# or: SELECT domains.id, domains.name FROM "domains" INNER JOIN "addresses" ON
#     "domains".id = "addresses".domain_id WHERE (("addresses".mailbox_id = 1))
#      GROUP BY domains.id, domains.name
m.domains.all(:select => 'domains.id, domains.name', 
  :group => 'domains.id, domains.name')

The problem for me is that I don’t know which solution is better. When I don’t specify any other conditions, the PostgreSQL query planner favours solution number two (working as expected), but if I add conditions to the queries, it comes down to “Unique” vs. “Group”:

With “DISTINCT”:

 Unique  (cost=16.56..16.57 rows=1 width=150)
   ->  Sort  (cost=16.56..16.56 rows=1 width=150)
         Sort Key: domains.name, domains.id
         ->  Nested Loop  (cost=0.00..16.55 rows=1 width=150)
               ->  Index Scan using index_addresses_on_mailbox_id on addresses  (cost=0.00..8.27 rows=1 width=4)
                     Index Cond: (mailbox_id = 1)
               ->  Index Scan using domains_pkey on domains  (cost=0.00..8.27 rows=1 width=150)
                     Index Cond: (domains.id = addresses.domain_id)
                     Filter: (domains.active AND domains.selfmgmt)
(9 rows)

With “GROUP BY”:

Group  (cost=16.56..16.57 rows=1 width=150)
   ->  Sort  (cost=16.56..16.56 rows=1 width=150)
         Sort Key: domains.name, domains.id
         ->  Nested Loop  (cost=0.00..16.55 rows=1 width=150)
               ->  Index Scan using index_addresses_on_mailbox_id on addresses  (cost=0.00..8.27 rows=1 width=4)
                     Index Cond: (mailbox_id = 1)
               ->  Index Scan using domains_pkey on domains  (cost=0.00..8.27 rows=1 width=150)
                     Index Cond: (domains.id = addresses.domain_id)
                     Filter: (domains.active AND domains.selfmgmt)
(9 rows)

I’m really unsure how to determine the better way to retrieve these data. My instincts tell me to go with “GROUP BY”, but I was unable to find any documentation specific enough to solve this problem.

Should I use “:group” or “:select => ‘DISTINCT'”? Is that choice the same with other modern RDBMS like e.g. Oracle, DB2 or MySQL (I don’t have access to those, so I can’t perform tests)?

  • 1 1 Answer
  • 0 Views
  • 0 Followers
  • 0
Share
  • Facebook
  • Report

Leave an answer
Cancel reply

You must login to add an answer.

Forgot Password?

Need An Account, Sign Up Here

1 Answer

  • Voted
  • Oldest
  • Recent
  • Random
  1. Editorial Team
    Editorial Team
    2026-05-12T11:43:09+00:00Added an answer on May 12, 2026 at 11:43 am

    If you’re using Postgresql < 8.4 (which I guess you are, given the plans) – it’s usually better to use GROUP BY instead of DISTINCT as its plan is simply more efficient.

    In 8.4 there is no difference as DISTINCT was “taught” to be able to use group operators as well.

    • 0
    • Reply
    • Share
      Share
      • Share on Facebook
      • Share on Twitter
      • Share on LinkedIn
      • Share on WhatsApp
      • Report

Sidebar

Related Questions

Let me explain best with an example. Say you have node class that can
Let's say I have a custom class CustomClass, and I have a collection deriving
Let's say I have the following structure: abstract class Hand {} class Rock extends
Let's assume that a user votes for some movies in a scale of 1
Let's say I have the following classes : public class MyProductCode { private String
Let assume we have two activities. A - main activity, that is home launcher
Let's say on a page I have alot of this repeated: <div class=entry> <h4>Magic:</h4>
Let's assume that we are building a high traffic site that will be used
Let's say you have a class called Customer, which contains the following fields: UserName
Let's say I'm writing a PHP (>= 5.0) class that's meant to be a

Explore

  • Home
  • Add group
  • Groups page
  • Communities
  • Questions
    • New Questions
    • Trending Questions
    • Must read Questions
    • Hot Questions
  • Polls
  • Tags
  • Badges
  • Users
  • Help
  • SEARCH

Footer

© 2021 The Archive Base. All Rights Reserved
With Love by The Archive Base

Insert/edit link

Enter the destination URL

Or link to existing content

    No search term specified. Showing recent items. Search or use up and down arrow keys to select an item.