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Home/ Questions/Q 206585
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Editorial Team
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Editorial Team
Asked: May 11, 20262026-05-11T17:39:33+00:00 2026-05-11T17:39:33+00:00

Let’s assume we have the following structure: index.php config.inc.php \ lib \ lib \

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Let’s assume we have the following structure:

index.php
config.inc.php
\ lib
\ lib \ common.php

Several parameters like database name, user & co are configured in config.inc.php. What is the proper way to access them i.e. from a function located in \lib\common.php. Do I really have to do an include_once("config.inc.php") within each function there?

It doesn’t seem to work if:

  • config.inc.php is included once once in index.php, before including \lib\common.php there
  • if config.inc.php defines all variables before including \lib\common.php and all other files (this way I would only have to include config.inc.php in all “central” files at the level of index.php
  • neither does it work if config.inc.php is included at the top of \lib\common.php

Many thanks – I wasn’t able to find a solution with Google!

Solution

I included config.inc.php once in index.php (as suggested by Galen) and used global (as suggested by David). Everything is working as I would expect it, many thanks!

Later on I will definitely look into auto_prepend as suggested by n3rd, tkx for that as well!

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  1. Editorial Team
    Editorial Team
    2026-05-11T17:39:34+00:00Added an answer on May 11, 2026 at 5:39 pm

    You have to use the global keyword to access variables which were defined outside of a function:

    $var1 = "muh";
    $var2 = "foo";
    
    function test() {
        global $var1;
        echo "var1=$var1; var2=$var2\n";
    }
    

    will print "var1=muh; var2=".

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