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Home/ Questions/Q 6782367
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Editorial Team
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Editorial Team
Asked: May 26, 20262026-05-26T16:43:58+00:00 2026-05-26T16:43:58+00:00

Let’s consider the following code snippet in Java. package escape; final public class Main

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Let’s consider the following code snippet in Java.

package escape;

final public class Main
{
    public static void main(String[] args)
    {            
         String s = "abc/xyz";
         System.out.println(s.replaceAll("/", "\\\\"));
    }
}

I just want to replace “/” with “\” in the above String abc/xyz and which is done and displays abc\xyz as expected but I couldn’t get why it requires back slashes four times. It looks like two back slashes are sufficient. Why such is not a case?

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  1. Editorial Team
    Editorial Team
    2026-05-26T16:43:59+00:00Added an answer on May 26, 2026 at 4:43 pm

    The reason is that String.replaceAll uses regular expressions (and actually calls Matcher.replaceAll which does document this). In regular expressions you have to escape the ‘\’ also in string literals you have to escape the ‘\’. Your 4 slashes are two slashes in the java string. And thereby an escaped slash in the regular expression.

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