Sign Up

Sign Up to our social questions and Answers Engine to ask questions, answer people’s questions, and connect with other people.

Have an account? Sign In

Have an account? Sign In Now

Sign In

Login to our social questions & Answers Engine to ask questions answer people’s questions & connect with other people.

Sign Up Here

Forgot Password?

Don't have account, Sign Up Here

Forgot Password

Lost your password? Please enter your email address. You will receive a link and will create a new password via email.

Have an account? Sign In Now

You must login to ask a question.

Forgot Password?

Need An Account, Sign Up Here

Please briefly explain why you feel this question should be reported.

Please briefly explain why you feel this answer should be reported.

Please briefly explain why you feel this user should be reported.

Sign InSign Up

The Archive Base

The Archive Base Logo The Archive Base Logo

The Archive Base Navigation

  • SEARCH
  • Home
  • About Us
  • Blog
  • Contact Us
Search
Ask A Question

Mobile menu

Close
Ask a Question
  • Home
  • Add group
  • Groups page
  • Feed
  • User Profile
  • Communities
  • Questions
    • New Questions
    • Trending Questions
    • Must read Questions
    • Hot Questions
  • Polls
  • Tags
  • Badges
  • Buy Points
  • Users
  • Help
  • Buy Theme
  • SEARCH
Home/ Questions/Q 7657389
In Process

The Archive Base Latest Questions

Editorial Team
  • 0
Editorial Team
Asked: May 31, 20262026-05-31T13:01:12+00:00 2026-05-31T13:01:12+00:00

Let’s declare a def and an equivalent function as a val: scala> def optional(x:Int):Option[String]

  • 0

Let’s declare a def and an equivalent function as a val:

scala> def optional(x:Int):Option[String] = None
optional: (x: Int)Option[String]

scala> val optional2:(Int)=>Option[String] = (i:Int) => None
optional2: Int => Option[String] = <function1>

Now why doesn’t this work?

scala> List(1).flatMap(optional2)
<console>:9: error: type mismatch;
 found   : Int => Option[String]
 required: Int => scala.collection.GenTraversableOnce[?]
              List(1).flatMap(optional2)
                              ^

While both of these do?

scala> List(1).flatMap(optional)
res4: List[String] = List()

scala> List(1).flatMap(optional2(_))
res5: List[String] = List()

Since Option is not a subtype of GenTraversableOnce, I think this must have something to do with implicits, but I can’t figure out what exactly it is. I am using Scala 2.9.1.

  • 1 1 Answer
  • 0 Views
  • 0 Followers
  • 0
Share
  • Facebook
  • Report

Leave an answer
Cancel reply

You must login to add an answer.

Forgot Password?

Need An Account, Sign Up Here

1 Answer

  • Voted
  • Oldest
  • Recent
  • Random
  1. Editorial Team
    Editorial Team
    2026-05-31T13:01:13+00:00Added an answer on May 31, 2026 at 1:01 pm

    The implicit conversion Option.option2Iterable is what makes List(1).flatMap(optional) and List(1).flatMap(optional2(_)) work.

    Your issue can be boiled down to the implicit conversion not being picked up:

    scala> val optional2:(Int)=>Option[String] = (i:Int) => None
    optional2: Int => Option[String] = <function1>
    
    scala> (optional2(_)): Function[Int, Iterable[String]]
    res0: Int => Iterable[String] = <function1>
    
    scala> (optional2): Function[Int, Iterable[String]]
    <console>:9: error: type mismatch;
     found   : Int => Option[String]
     required: Int => Iterable[String]
    

    When you use the underscore, the compiler attempts to type the function and provide the necessary implicit conversion. When you just provide optional2, there is no implicit conversion that applies.

    • 0
    • Reply
    • Share
      Share
      • Share on Facebook
      • Share on Twitter
      • Share on LinkedIn
      • Share on WhatsApp
      • Report

Sidebar

Related Questions

I have a string like this: La Torre Eiffel paragonata all&#8217;Everest What PHP function
Let's say we have a simple function defined in a pseudo language. List<Numbers> SortNumbers(List<Numbers>
Let's take a common example how a haskell function can be called from a
Let's say I have the string: hello world; some random text; foo; How could
Let's suppose I have this piece of code. foreach(string value in myList) { string
Let simplify the question: All I need is to explode() string by a comma
Let's say I have the following function in C#: void ProcessResults() { using (FormProgress
Let's say that I have classes like this: public class Parent { public int
Let's say we have the following table: CREATE TABLE T ( ID INT, String1
Let's say I have the following code: <ul> <li data-val=1>1</li> <li data-val=4>2</li> <li data-val=2>3</li>

Explore

  • Home
  • Add group
  • Groups page
  • Communities
  • Questions
    • New Questions
    • Trending Questions
    • Must read Questions
    • Hot Questions
  • Polls
  • Tags
  • Badges
  • Users
  • Help
  • SEARCH

Footer

© 2021 The Archive Base. All Rights Reserved
With Love by The Archive Base

Insert/edit link

Enter the destination URL

Or link to existing content

    No search term specified. Showing recent items. Search or use up and down arrow keys to select an item.