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Home/ Questions/Q 7984311
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Editorial Team
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Editorial Team
Asked: June 4, 20262026-06-04T11:13:46+00:00 2026-06-04T11:13:46+00:00

Let’s define this simple code : class Foo @foo = ‘blah’ console.log(@foo) class Bar

  • 0

Let’s define this simple code :

class Foo
  @foo = 'blah'
  console.log(@foo)

class Bar extends Foo
  constructor: () ->
    console.log(@foo)

  bar: () ->
    console.log(@foo)

b = new Bar
b.bar()

And result is :

blah
undefined
undefined

How can I access @foo in inherited class ?

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-04T11:13:48+00:00Added an answer on June 4, 2026 at 11:13 am

    You actually want to write

    console.log(@constructor.foo)
    

    in Bar‘s constructor. (Working example here.) @constructor points to the class (Bar), which inherits the static properties of Foo. Those properties aren’t on the instance, which is what @ points to from the constructor.

    (Yes, it’s weird that it’s @constructor rather than @class, but that’s because obj.constructor is a JavaScript-ism, not a special CoffeeScript syntax.)

    To clarify further: In the class body, @ points to the class. In the constructor, @ points to the instance. Hence the apparent inconsistency. I devote a lot of time to this in the chapter on classes in my book, CoffeeScript: Accelerated JavaScript Development.

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