Question

Lets have an array of type int:-

        int arr[5]; 

Now,

       if arr[0] is at address 100 then
       Why do we have;
       arr[1] at address 102 , 
       arr[2] at address 104 and so on. 

Instead of

       arr[1] at address 101 , 
       arr[2] at address 102 and so on. 

Is it because an integer takes 2 bytes?

Does each memory block has 1 Byte capacity (whether it is 32 bit processor or 64 bit)?

Answer 1

Your first example is consistent with 16-bit ints.

As to your second example (&arr[0]==100, &arr[1]==101, &arr[2]==103), this can’t possibly be a valid layout since the distance between consecutive elements varies between the first pair and the second.