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Home/ Questions/Q 9281939
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Editorial Team
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Editorial Team
Asked: June 18, 20262026-06-18T18:14:45+00:00 2026-06-18T18:14:45+00:00

Let’s have an example to declare my concern: Suppose we have a Table (Tags)

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Let’s have an example to declare my concern:
Suppose we have a Table (Tags) which has two columns like this

UserID -------------------------------- Tag
1 -------------------------------------- SQL
1 -------------------------------------- Select
1 -------------------------------------- DB
2 -------------------------------------- SQL
2 -------------------------------------- Programming
2 -------------------------------------- Code
2 -------------------------------------- Software
3 -------------------------------------- Code
4 -------------------------------------- SQL
4 -------------------------------------- Code

I need to count DISTINCT co-occurrences for each tag based on UserID

So, the output should be like this (with Order by Co-occurrences desc):

Tag -------------------------------- Co-occurrences
---------------------------------------------
SQL --------------------------------------- 5
Programming ------------------------------- 3
Code -------------------------------------- 3
Software ---------------------------------- 3
Select ------------------------------------ 2
DB ---------------------------------------- 2

This is just an example..

How can I make a Select statement that can do this?

I came up with one way but for only ONE specific tag:

SELECT count (distinct (Tag)) - 1 as Co_occurrences
FROM Tags
WHERE Tag is NOT NULL and UserID in
    (   SELECT UserID
        FROM Tags 
        where tag = 'SQL')

Is it possible to change the above statement to make it general for all tags in the table?

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  1. Editorial Team
    Editorial Team
    2026-06-18T18:14:46+00:00Added an answer on June 18, 2026 at 6:14 pm
    SELECT t2.tag, count (distinct (t1.Tag)) - 1 as Co_occurrences
    FROM Tags t1 inner join 
        Tags t2 on t1.UserId = t2.UserId 
    GROUP BY t2.tag    
    ORDER BY count (distinct (t1.Tag)) desc      
    
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