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Home/ Questions/Q 6806215
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Editorial Team
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Editorial Team
Asked: May 26, 20262026-05-26T19:41:00+00:00 2026-05-26T19:41:00+00:00

Let’s look at the following day-to-day example of Java. package loop; final public class

  • 0

Let’s look at the following day-to-day example of Java.

package loop;

final public class Main 
{
    public static void main(String[] args) 
    {
         long temp=1000000000;

        while(temp--!=0)
        {
            temp-=temp++;
            System.out.println("Inside loop = "+temp);
        }
        System.out.println("Outside loop = "+temp);
    }
}

In the above simple code, the while loop iterates over only once though the local variable temp of type long contains a large value which is 1000000000.


Through the statement System.out.println("Inside loop = "+temp);, it displays Inside loop = 0 and through this statement System.out.println("Outside loop = "+temp);, it displays Outside loop = -1. Why is it so?

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  1. Editorial Team
    Editorial Team
    2026-05-26T19:41:00+00:00Added an answer on May 26, 2026 at 7:41 pm

    because when it hits the while loop for the last time, it does a temp–

    ie…. temp == 0, so it will quit the while loop, and do a — after the comparison.

    the joys of post increment/decrement.

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