Question

Lets say for example there are 5 records shown on screen. I want the $questionnum to display the number 5, but it keeps stating that $questionnum is 0. How Can I get the number of the number of rows actually match with the number of rows which are outputted on screen. E.G if 5 rows then display number 5, if 3 rows display number 3 and etc.

Below is code:

 // Execute
    if (!$stmt->execute()) {
      die("Error executing statement: $stmt->error"); 
    }

    $stmt->store_result();

    // This will hold the search results
    $searchResults = array();
    $searchOption = array();

    // Fetch the results into an array
    if (!$stmt->num_rows()) {
      $stmt->bind_result($dbQuestionContent,$dbOptionType); 
      while ($stmt->fetch()) {
        $searchResults[] = $dbQuestionContent;
        $searchOption[] = $dbOptionType;
      }
    }

    if (isset($_GET['searchQuestion'])) {

      // If $terms is not empty we did a query
      if (!empty($terms)) {

          $questionnum = $stmt->num_rows;

        // If $searchResults is not empty we got results
        if (!empty($searchResults)) {
         echo"<p>Number of Questions Shown from the Search: <strong>$questionnum</strong></p>";
          echo "<table border='1' id='resulttbl'>
          foreach ($searchResults as $key=>$question) {
            echo '<tr class="questiontd"><td>'.htmlspecialchars($question).'</td>';
            echo '<td class="optiontypetd">'.htmlspecialchars($searchOption[$key]).'</td>';
    }
          echo "</table>";
    }

Answer 1

Since you are already storing results in the array, just do

$questionnum = sizeof($searchOption);