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Home/ Questions/Q 8891159
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Editorial Team
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Editorial Team
Asked: June 14, 20262026-06-14T22:40:02+00:00 2026-06-14T22:40:02+00:00

Let’s say for instance that we have a class Board with many fields (i.e.

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Let’s say for instance that we have a class Board with many fields (i.e. a rather complex class). We instantiate a Board like so:

Board b = new Board();

Note that for the sake of this example, I am not entering any parameters into the constructor, though in a real example, those may be necessary. If we were to then instantiate a new instance of Board and set it equal to be like so:

Board c = b;

This would not actually create a new board. From what I know, c and b now point to the same area of memory, the same Board object. So, if I were to change something about b, say be incrementing an integer field, like so:

b.count++;//Assume count is an integer field in the Board class.

The value c.count should be incremented as well. However, when I do this myself, it doesn’t work. b.count is incremented, yet c.count is not.
Can anyone explain to me why this happens? This effect is something I want to have happen, thus any advice on how to implement this would be very helpful (General examples are fine).

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  1. Editorial Team
    Editorial Team
    2026-06-14T22:40:04+00:00Added an answer on June 14, 2026 at 10:40 pm

    Wrong again:

    package cruft;
    
    /**
     * Board description here
     * @author Michael
     * @link
     * @since 11/26/12 6:46 PM
     */
    public class Board {
    
        public int count;
    
        public static void main(String[] args) {
            Board b = new Board();
            Board c = b;
            System.out.println("b before: " + b);
            System.out.println("c before: " + c);
    
            ++b.count;
    
            System.out.println("b after : " + b);
            System.out.println("c after : " + c);
        }
    
        @Override
        public String toString() {
            final StringBuilder sb = new StringBuilder();
            sb.append("Board");
            sb.append("{count=").append(count);
            sb.append('}');
            return sb.toString();
        }
    }
    
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