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Home/ Questions/Q 8670941
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Editorial Team
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Editorial Team
Asked: June 12, 20262026-06-12T18:49:33+00:00 2026-06-12T18:49:33+00:00

Let’s say, for simplicity, this is how my page is set up: class TFS

  • 0

Let’s say, for simplicity, this is how my page is set up:

class TFS extends PHP_db
{
    public function execute() {
        class Dostuff {
            public static function doit() {
                return "wee";
            }
        }
    Now here I can use Dostuff:doit() successfully
    And also $this->db->functionhere() which is from the PHP_db is also successful from here

    }
}

I need to figure how to call $this->db->functionhere() from within the doit() function inside the Dostuff class..

I have already tried this in the Dostuff class:

protected $parent_object;
public function __construct( $object ) {
    $this->parent_object = $object;
 }

and this from the execute() function: $dostuffclass = new Dostuff($this);

But then when I try to use $parent_object->db->functionhere() it doesn’t work, telling me it’s not an object.

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-12T18:49:34+00:00Added an answer on June 12, 2026 at 6:49 pm

    You could pass the $this context to the internal DoStuff class as a parameter, for example:

    class TFS extends PHP_db
    {
        public function execute() {
            class Dostuff {
                public static function doit($somevar) {
                    $somevar->functionhere();
                    ^^^^ <-- add this
                    return "wee";
                }
            }
        }
    }
    

    The internal class DoStuff does not need to know anything about the $this context you are referring to, since you are sending a reference to an existing class instance to it as a parameter.

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