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Home/ Questions/Q 8448053
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Editorial Team
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Editorial Team
Asked: June 10, 20262026-06-10T10:19:33+00:00 2026-06-10T10:19:33+00:00

Let’s say I am using rendered as basically a case statement. I have a

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Let’s say I am using rendered as basically a case statement. I have a label and message for an input field, but I want the field itself to change depending on the case. As such:

<p:inputText id="foo" value="#{myBean.params[paramKey]}" 
   rendered="#{paramIsInput}" />
<p:calendar  id="foo" value="#{myBean.params[paramKey]}" 
   rendered="#{paramIsCalendar}" />

If I do that then I get the following error: java.lang.IllegalStateException: Component ID j_idt64:foo has already been found in the view.

As a workaround I created lots of labels/messages for each param type and changed their ids. But this brings my question. If only one component with an id is actually rendered, why would it matter that I have multiple defined in my jsf file? Is there a way to keep them with all the same ID?

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  1. Editorial Team
    Editorial Team
    2026-06-10T10:19:34+00:00Added an answer on June 10, 2026 at 10:19 am

    If only one component with an id is actually rendered, why would it matter that I have multiple defined in my jsf file?

    How would JSF know that only one component will be rendered? You are using EL in rendered and both can evaluate to true. Here is the documentation which says you can’t have duplicate ids inside a naming container.

    The specified identifier must be unique among all the components (including facets) that are descendents of the nearest ancestor UIComponent that is a NamingContainer, or within the scope of the entire component tree if there is no such ancestor that is a NamingContainer.

    –

    Is there a way to keep them with all the same ID?

    In case you still want to have same ids on more than one components you need to separate the naming container.

    You can use PanelGrid as a naming container.

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