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Home/ Questions/Q 7637771
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Editorial Team
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Editorial Team
Asked: May 31, 20262026-05-31T08:01:07+00:00 2026-05-31T08:01:07+00:00

Lets say I have 2 vectors: a=[0 1 0 1 1 0 1 0

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Lets say I have 2 vectors:

a=[0 1 0 1 1 0 1 0 0 0 1 1 1];
b=[1 1 1 1 1 1 2 2 2 3 3 3 3];

For every group of numbers in b I want to cumsum, so that the result should look like that:

c=[1 3;2 1;3 3]

That means that I have for the ones in b 3 ones in a, for group two in b I have only one one in a etc.

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  1. Editorial Team
    Editorial Team
    2026-05-31T08:01:08+00:00Added an answer on May 31, 2026 at 8:01 am

    If you’re looking for a solution where b can be anything, then a combination of hist and unique will help:

    num = unique(b(logical(a))); %# identify the numbers in b with non-zero counts
    cts = hist(b(logical(a)),num); %# count
    c = [num(:),cts(:)]; %# combine. 
    

    If you want the first column of c to go from 1 to the maximum of b, then you can rewrite the first line as num=1:max(b), and you’ll also get rows in c where the counts are zero.

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