Sign Up

Sign Up to our social questions and Answers Engine to ask questions, answer people’s questions, and connect with other people.

Have an account? Sign In

Have an account? Sign In Now

Sign In

Login to our social questions & Answers Engine to ask questions answer people’s questions & connect with other people.

Sign Up Here

Forgot Password?

Don't have account, Sign Up Here

Forgot Password

Lost your password? Please enter your email address. You will receive a link and will create a new password via email.

Have an account? Sign In Now

You must login to ask a question.

Forgot Password?

Need An Account, Sign Up Here

Please briefly explain why you feel this question should be reported.

Please briefly explain why you feel this answer should be reported.

Please briefly explain why you feel this user should be reported.

Sign InSign Up

The Archive Base

The Archive Base Logo The Archive Base Logo

The Archive Base Navigation

  • SEARCH
  • Home
  • About Us
  • Blog
  • Contact Us
Search
Ask A Question

Mobile menu

Close
Ask a Question
  • Home
  • Add group
  • Groups page
  • Feed
  • User Profile
  • Communities
  • Questions
    • New Questions
    • Trending Questions
    • Must read Questions
    • Hot Questions
  • Polls
  • Tags
  • Badges
  • Buy Points
  • Users
  • Help
  • Buy Theme
  • SEARCH
Home/ Questions/Q 6963427
In Process

The Archive Base Latest Questions

Editorial Team
  • 0
Editorial Team
Asked: May 27, 20262026-05-27T15:47:21+00:00 2026-05-27T15:47:21+00:00

Let’s say I have 4 x img tags with the same class and each

  • 0

Let’s say I have 4 x img tags with the same class and each has different url. I can retrieve each url with this code:

$('.userPicture img').each(function(){
    var getImageLink = $(this).attr('src');
    console.log(getImageLink)
});

Console.log:

http://link1.com
http://link2.com
http://link3.com
http://link4.com

The quesion is how to append each link only once per class?

$.each(getImageLink, function(i) {
    $('.aboutInfo').eq(i).append('<p><a href="'+getImageLink+'"></a></p>');

});

Best result I can get is:

.aboutInfo
http://link1.com
http://link2.com
http://link3.com
http://link4.com

.aboutInfo
http://link1.com
http://link2.com
http://link3.com
http://link4.com

what I need is:

.aboutInfo
http://link1.com

.aboutInfo
http://link2.com

etc…

I can’t figure it out by myselft 🙁

  • 1 1 Answer
  • 0 Views
  • 0 Followers
  • 0
Share
  • Facebook
  • Report

Leave an answer
Cancel reply

You must login to add an answer.

Forgot Password?

Need An Account, Sign Up Here

1 Answer

  • Voted
  • Oldest
  • Recent
  • Random
  1. Editorial Team
    Editorial Team
    2026-05-27T15:47:25+00:00Added an answer on May 27, 2026 at 3:47 pm

    this should work

    $('.userPicture img').each(function(i, el){
      var getImageLink = $(el).attr('src');
      $('.aboutInfo').eq(i).append('<p><a href="'+getImageLink+'"></a></p>');
    });
    

    The key is to do the appending inside the .each loop…that way getImageLink will be the proper value (it’s in scope) and it will append to each link once.

    UPDATE: To answer the question posed in the comments, you don’t need to have text in a link to have it work. The CSS could simply be this:

    .aboutInfo {
      background: url(http://server.com/images/20x100-image.png) center left no-repeat;
      height: 20px;
      width: 100px;
      display: block;
    }
    

    Either way, the question of why the link has no text is not really the point of the OP’s question, but hopefully this explanation will help anyone who’s curious.

    • 0
    • Reply
    • Share
      Share
      • Share on Facebook
      • Share on Twitter
      • Share on LinkedIn
      • Share on WhatsApp
      • Report

Sidebar

Related Questions

Let's say on a page I have alot of this repeated: <div class=entry> <h4>Magic:</h4>
Let's say I have table with column 'URL' whrere I store urls like this
Let's say that I have classes like this: public class Parent { public int
Let's say I have the following models class Photo(models.Model): tags = models.ManyToManyField(Tag) class Tag(models.Model):
Let's say you have a class called Customer, which contains the following fields: UserName
Let's say I can call a method like this: core::get() . What is the
Let's say I have a text file composed like this ##### typeofthread1 ##### typeofthread2
Let's say I have this code: <p dataname=description> Hello this is a description. <a
Let's say that I have a set of relations that looks like this: relations
Let's say I have a dataset, which can be neatly classified using weka's J48

Explore

  • Home
  • Add group
  • Groups page
  • Communities
  • Questions
    • New Questions
    • Trending Questions
    • Must read Questions
    • Hot Questions
  • Polls
  • Tags
  • Badges
  • Users
  • Help
  • SEARCH

Footer

© 2021 The Archive Base. All Rights Reserved
With Love by The Archive Base

Insert/edit link

Enter the destination URL

Or link to existing content

    No search term specified. Showing recent items. Search or use up and down arrow keys to select an item.