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Home/ Questions/Q 8860995
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Editorial Team
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Editorial Team
Asked: June 14, 20262026-06-14T15:23:29+00:00 2026-06-14T15:23:29+00:00

Let’s say I have a class called Number , and I intend to do

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Let’s say I have a class called Number, and I intend to do a lot of equality comparisons of Number objects. I am concerned about the “overhead” (class comparison, etc…) of the generic Number::equals(Object o) method. In this case, is it useful to provide a method such as Number::isEqualTo(Number other) as an alternative to Number::equals(Object o)? Is this a common pattern? Or do JVMs currently optimize well enough that there is no advantage to doing this?

Here’s a code example:

public class Number {
    int _value;

    Number(int value) {
        _value = value;
    }

    @Override
    public boolean equals(final Object o) {
        if (o == this) return true;
        if (o == null) return false;
        if (o.getClass() != getClass()) return false;
        return isEqualTo((Number)o);
    }

    public boolean isEqualTo(final Number other) {
        return _value == other._value;
    }

    public static void main(String[] args) {
        Number one = new Number(1);
        Number two = new Number(2);
        if (!one.isEqualTo(two)) {
            System.out.println("fast comparison?");
        }
        if (!one.equals(two)) {
            System.out.println("slow comparison?");
        }
    }
}
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  1. Editorial Team
    Editorial Team
    2026-06-14T15:23:30+00:00Added an answer on June 14, 2026 at 3:23 pm

    You may even provide an overload of equals itself: equals(Number). If you implement it very carefully (to be behaviorally indistinguishable from equals(Object)), you can achieve a minuscule speedup by avoiding a checked downcast in certain cases. Note that you are still going to have to check a.getClass() == b.getClass() so the difference is vanishingly small.

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