Question

Lets say I have a class named Car and another which inherits from Car called SuperCar. How can I ensure that Car’s costructor is called in SuperCar’s constructor? Do I simply do: Car.Car(//args);?

Thanks

Answer 1

In SuperCar constructor add : Car(... your arguments ...) between constructor header and constructor body.

Exemple with code:

#include <iostream>
using namespace std;

class Car {
    public:
    Car() { }
    // Oh, there is several constructors...
    Car(int weight){
        cout << "Car weight is " << weight << endl;
    }
};

class SuperCar: public Car {
    public:
    // we call the right constructor for Car, detected by call arguments
    // relying on usual function overloading mechanism
    SuperCar(int weight, int height) : Car(weight) {
        cout << "SuperCar height " << height << endl;
    }
};

int main(){
    SuperCar(1, 10);
}

PS: By the way calling SuperCar a subclass of Car is confusing, you should probably avoid that.