Question

Let’s say I have a command:

mysql -h localhost -u root -pmypassword dev<file01.sql;

I have many sql files to run: file02.sql, file03.sql, … file99.sql

I want to generate a bash script like this to run all these sql files sequentially.

a portion of the bash script reads like this:

mysql -h localhost -u root -pmypassword dev<file01.sql;
mysql -h localhost -u root -pmypassword dev<file02.sql;
mysql -h localhost -u root -pmypassword dev<file03.sql;


mysql -h localhost -u root -pmypassword dev<file99.sql;

All these lines are of the same pattern, only file name (filexx.sql) changes.

All the filexx.sql are in the same directory.

I usually generate the bash script in Excel. I know this can be done in bash easily, I just do not know how. Could you advise on how to generate this?

Thank you very much.

Answer 1

If you want to execute those statements:

for fileid in $(seq 1 99); do
    filename=$(printf "file%02d.sql" $fileid)
    mysql -h localhost -u root -pmypassword dev < $filename
done

But if you only want to generate them:

for fileid in $(seq 1 99); do
    filename=$(printf "file%02d.sql" $fileid)
    echo "mysql -h localhost -u root -pmypassword dev < $filename"
done