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Home/ Questions/Q 1039641
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Editorial Team
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Editorial Team
Asked: May 16, 20262026-05-16T15:07:32+00:00 2026-05-16T15:07:32+00:00

Lets say I have a database that looks like this: tblA: ID, Name, Sequence,

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Lets say I have a database that looks like this:

tblA:
ID, Name, Sequence, tblBID
1     a       5        14
2     b       3        15
3     c       3        16
4     d       3        17

tblB:
ID, Group
14    1
15    1
16    2
17    3

I would like to sequence A so that the sequences go 1…n for each group of B.
So in this case, the sequences going down should be 1,2,1,1.

The ordering needs to be consistent with the current ordering, but there are no guarantees as to the current ordering.

I am not exactly a sql master and I am sure there is a fairly easy way to do this, but I really don’t know the right route to take. Any hints?

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-16T15:07:32+00:00Added an answer on May 16, 2026 at 3:07 pm

    If you are using SQL Server 2005+ or higher, you can use a ranking function:

    Select tblA.Id, tblA.Name
        , Row_Number() Over ( Partition By tblB.[Group] Order By tblA.Id ) As Sequence
        , tblA.tblBID
    From tblA
        Join tblB
            On tblB.tblBID = tblB.ID
    

    Row_Number ranking function.

    Here’s another solution that would work in SQL Server 2000 and prior.

    Select A.Id, A.Name
        , (Select Count(*)
            From tblB As B1
            Where B1.[Group] = B.[Group]
                And B1.Id < B.ID) + 1 As Sequence
        , A.tblBID
    From tblA As A
        Join tblB As B
            On B.Id = A.tblBID
    

    EDIT

    Also want to make it clear that I want to actually update tblA to reflect the proper sequences.

    In SQL Server, you can use their proprietary From clause in an Update statement like so:

    Update tblA
    Set Sequence =  (
                    Select Count(*)
                    From tblB As B1
                    Where B1.[Group] = B.[Group]
                        And B1.Id < B.ID
                    ) + 1
    From tblA As A
        Join tblB As B
            On B.Id = A.tblBID
    

    The Hoyle ANSI solution might be something like:

    Update tblA
    Set Sequence = (
                    Select (Select Count(*)
                            From tblB As B1
                            Where B1.[Group] = B.[Group]
                                And B1.Id < B.ID) + 1
                    From tblA As A
                        Join tblB As B
                            On B.Id = A.tblBID
                    Where A.Id = tblA.Id
                    )
    

    EDIT

    Can we do that [the inner group] comparison based on A.Sequence instead of B.ID?

    Select A1.*
        , (Select Count(*)
            From tblB As B2
                Join tblA As A2
                    On A2.tblBID = B2.Id
            Where B2.[Group] = B1.[Group]
                And A2.Sequence < A1.Sequence) + 1
    From tblA As A1
        Join tblB As B1
            On B1.Id = A1.tblBID
    
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