Question

Let’s say I have a function called dummy defined in the following way:

void dummy(CMyString& mystr)
{
   mystr.print(); //show
}

CMyString would be my own implementation of strings using an array of chars.

int main()
{
   dummy("This is a test!");
   return 0;
}

I’d like the following program to print out : “This is a test!”.
Is this possible?

Answer 1

Yes it is, you just need to provide a non-explicit conversion constructor to CMyString:

class CMyString
{
public:
    CMyString(const char* x); 
    //.....
};

and, of course, implement the CMyString::print method. After this you need to change the parameter to

void dummy(const CMyString& mystr)

(and mark the print method as const) because you can’t bind a temp to a non-const reference.