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Home/ Questions/Q 8851671
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Editorial Team
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Editorial Team
Asked: June 14, 20262026-06-14T13:12:43+00:00 2026-06-14T13:12:43+00:00

Let’s say I have a higher order function f :: (a -> b) ->

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Let’s say I have a higher order function f :: (a -> b) -> (a -> b). But f only behaves properly if the input function is surjective. Is there anyway to force this to happen in Haskell? For example, I really want f‘s type signature to be something like:

f :: (Surjective (a -> b)) => (a -> b) -> (a -> b)

But this doesn’t work because I don’t want all functions of the type a -> b to be declared to be surjective, only some of them. For example, maybe f converts a surjective function into a non-surjective function.

We could wrap the functions in a special data type data Surjective f = Surjective f, and define

f :: Surjective (a -> b) -> (a -> b)

but this would make it difficult to assign multiple properties to a function.

Is there any convenient way to do this in practice? Is this even possible in theory?

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  1. Editorial Team
    Editorial Team
    2026-06-14T13:12:44+00:00Added an answer on June 14, 2026 at 1:12 pm

    This is an example of how surjectivity can be expressed in Agda:

    module Surjectivity where
    
    open import Data.Product using ( ∃; ,_ )
    open import Relation.Binary.PropositionalEquality using ( _≡_; refl )
    
    Surjective : ∀ {a b} {A : Set a} {B : Set b} → (A → B) → Set _
    Surjective {A = A} {B = B} f = ∀ (y : B) → ∃ λ (x : A) → f x ≡ y
    

    For example, id is surjective (a simple proof):

    open import Function using ( id )
    
    id-is-surjective : ∀ {a} {A : Set a} → Surjective {A = A} id
    id-is-surjective _ = , refl
    

    Taking another identity function which works only for surjective functions:

    id-for-surjective's : ∀ {a b} {A : Set a} {B : Set b} → (F : A → B) → {proof : Surjective F} → A → B
    id-for-surjective's f = f
    

    we can pass id to id-for-surjective's with its surjectivity proof as witness:

    id′ : ∀ {a} {A : Set a} → A → A
    id′ = id-for-surjective's id {proof = id-is-surjective}
    

    so that id′ is the same function as id:

    id≡id′ : ∀ {a} {A : Set a} → id {A = A} ≡ id′
    id≡id′ = refl
    

    Trying to pass a non-surjective function to id-for-surjective's would be impossible:

    open import Data.Nat using ( ℕ )
    
    f : ℕ → ℕ
    f x = 1
    
    f′ : ℕ → ℕ
    f′ = id-for-surjective's f {proof = {!!}} -- (y : ℕ) → ∃ (λ x → f x ≡ y) (unprovable)
    

    Similary, many other properties can be expressed in such manner, Agda’s standard library already have necessary definitions (e.g. Function.Surjection, Function.Injection, Function.Bijection and other modules).

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