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Home/ Questions/Q 253315
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Editorial Team
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Editorial Team
Asked: May 11, 20262026-05-11T21:45:05+00:00 2026-05-11T21:45:05+00:00

let’s say I have a list a = [1,2,3] I’d like to increment every

  • 0

let’s say I have a list

a = [1,2,3]

I’d like to increment every item of that list in place. I want to do something as syntactically easy as

for item in a:
    item += 1

but in that example python uses just the value of item, not its actual reference, so when I’m finished with that loop a still returns [1,2,3] instead of [2,3,4]. I know I could do something like

a = map(lambda x:x+1, a)

but that doesn’t really fit into my current code and I’d hate to have to rewrite it :-\

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  1. Editorial Team
    Editorial Team
    2026-05-11T21:45:05+00:00Added an answer on May 11, 2026 at 9:45 pm

    Here ya go:

    # Your for loop should be rewritten as follows:
    for index in xrange(len(a)):
        a[index] += 1
    

    Incidentally, item IS a reference to the item in a, but of course you can’t assign a new value to an integer. For any mutable type, your code would work just fine:

    >>> a = [[1], [2], [3], [4]]
    >>> for item in a: item += [1]
    >>> a
    [[1,1], [2,1], [3,1], [4,1]]
    
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