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Home/ Questions/Q 8696267
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Editorial Team
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Editorial Team
Asked: June 13, 20262026-06-13T01:14:20+00:00 2026-06-13T01:14:20+00:00

Let’s say I have a logging setup like this in my Python script: import

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Let’s say I have a logging setup like this in my Python script:

import logging

logging.basicConfig(level=logging.DEBUG, stream=sys.stdout,
                    format='%(asctime)s %(levelname)s %(message)s',
                    datefmt='%a, %d %b %Y %H:%M:%S')
logging.info('info')
logging.error('error...')
logging.debug('debug...')

Is there a way I can have it wait to print to stdout until the script is finished running and sort the log messages by level before printing?

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-13T01:14:21+00:00Added an answer on June 13, 2026 at 1:14 am

    From the looks of it, the object passed to stream only needs to have a write method. This means you can create a list-like object which appends data when write is called — You can then sort the list-like object trivially before printing.

    import logging
    
    class LogList(list):
       def write(self,data):
           self.append(data)
    
    LL = LogList()
    logging.basicConfig(stream = LL,level=logging.DEBUG)
    logging.debug('This message should go to the log file')
    logging.info('So should this')
    logging.error('Wow, this is bad')
    logging.warning('And this, too')
    logging.debug('foobar')
    logging.warning('baz')
    
    for line in sorted(LL):
       print line[:-1]
    

    Of course, you might need to make your sort key a little more to pick up different levels. Something like:

    levels = {'DEBUG':0,'INFO':1,'WARNING':2,'ERROR':3}
    LL.sort(key = lambda x: levels[x.split(':')[0]])
    
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