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Home/ Questions/Q 9277691
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Editorial Team
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Editorial Team
Asked: June 18, 20262026-06-18T17:10:16+00:00 2026-06-18T17:10:16+00:00

Let’s say I have a method that calls another method with some parameters, something

  • 0

Let’s say I have a method that calls another method with some parameters, something like this:

   public void SomeMethod()
   {
      List<SomeObject> TheList = SomeQueryThatReturnsTheList();

      TheList = DoSomeWorkWithList(TheList);
   }

   public List<SomeObject> WorkForList(List<SomeObject> TheListAsParameter)
   {
      foreach (SomeObject x in TheListAsParameter)
      {
          ....
      }

      return TheListAsParameter;
   }

As you can see, the method WorkForList returns the list it received. My question is this: if I don’t return the list and rewrite the signature as public void WorkForList(List<SomeObject> TheListAsParameter) is pass by reference in c# going to mean that TheList in SomeMethod is going to be updated with the work that’s done in the WorkForList method? If so, will the following code work the same:

   public void SomeMethod()
   {
      List<SomeObject> TheList = SomeQueryThatReturnsTheList();

      DoSomeWorkWithList(TheList);
   }

   public void WorkForList(List<SomeObject> TheListAsParameter)
   {
        ....
   }

Thanks.

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  1. Editorial Team
    Editorial Team
    2026-06-18T17:10:18+00:00Added an answer on June 18, 2026 at 5:10 pm

    Well if you don’t use the ref keyword, its address will be passed by value, meaning you will be able to change its element, but you can’t initialized it or can’t assign it null. for example. If in your method you do:

    public void WorkForList(List<SomeObject> TheListAsParameter)
    {
      TheListAsParameter = null;
    } 
    

    You will not see the difference in the caller.

    You should see this article: Parameter passing in C# by Jon Skeet

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