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Home/ Questions/Q 3760388
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Editorial Team
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Editorial Team
Asked: May 19, 20262026-05-19T10:27:50+00:00 2026-05-19T10:27:50+00:00

Lets say I have a polymorphic class Structure like that class Base { //some

  • 0

Lets say I have a polymorphic class Structure like that

class Base
{
//some implementation
};

class Deriv: public Base
{
//implementation
}

class Case1
{
  boost::scoped_ptr<A> a_ //polymorphic data member owned by C
public:
  Case1(A* a):a_(a)
  {

  }
};
class Case2
{
  boost::scoped_ptr<A> a_ //polymorphic data member owned by C
public:
  Case2(std::auto_ptr<A> a):a_( a.release() )
  {

  }
};

And I’ve got a third class case1/2 which owns one of those polymorphic object described above. Now I need to pass a pointer to a Base/Deriv object to the constructor of the case1/2 class which takes ownership of this object. Should I pass this object as a smart pointer e.g. auto_ptr to make it clear I’m takin care of this object, or allow raw pointers( case 1 ) to allow a much simpler syntax like

Case1 c(new Deriv);
//compared to 
Case2 c(std::auto_ptr<Base>(new Deriv));
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  1. Editorial Team
    Editorial Team
    2026-05-19T10:27:51+00:00Added an answer on May 19, 2026 at 10:27 am

    You need to pass a smart pointer and you need to name that smart pointer (e.g., it can’t be a temporary):

    std::auto_ptr<Base> p(new Deriv);
    Case2 c(p); // this constructor would need to take the `auto_ptr` by reference 
                // so that it can steal ownership.
    

    In your first example, Case1 c(new Deriv);, the object could be leaked if an exception is thrown between when new Deriv is executed and when the Case1 object takes ownership of it in its constructor.

    In your second example, where you don’t name the smart pointer, the object could be leaked in some circumstances. Notably, this can happen if you have more than one argument to a function.

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