Sign Up

Sign Up to our social questions and Answers Engine to ask questions, answer people’s questions, and connect with other people.

Have an account? Sign In

Have an account? Sign In Now

Sign In

Login to our social questions & Answers Engine to ask questions answer people’s questions & connect with other people.

Sign Up Here

Forgot Password?

Don't have account, Sign Up Here

Forgot Password

Lost your password? Please enter your email address. You will receive a link and will create a new password via email.

Have an account? Sign In Now

You must login to ask a question.

Forgot Password?

Need An Account, Sign Up Here

Please briefly explain why you feel this question should be reported.

Please briefly explain why you feel this answer should be reported.

Please briefly explain why you feel this user should be reported.

Sign InSign Up

The Archive Base

The Archive Base Logo The Archive Base Logo

The Archive Base Navigation

  • Home
  • SEARCH
  • About Us
  • Blog
  • Contact Us
Search
Ask A Question

Mobile menu

Close
Ask a Question
  • Home
  • Add group
  • Groups page
  • Feed
  • User Profile
  • Communities
  • Questions
    • New Questions
    • Trending Questions
    • Must read Questions
    • Hot Questions
  • Polls
  • Tags
  • Badges
  • Buy Points
  • Users
  • Help
  • Buy Theme
  • SEARCH
Home/ Questions/Q 6757857
In Process

The Archive Base Latest Questions

Editorial Team
  • 0
Editorial Team
Asked: May 26, 20262026-05-26T13:42:20+00:00 2026-05-26T13:42:20+00:00

Let’s say I have a set of Django Models: class Article(models.Model): title = models.CharField(max_length=100,

  • 0

Let’s say I have a set of Django Models:

class Article(models.Model):
    title = models.CharField(max_length=100, default='')
    content = models.TextField(default='', blank=False)
    created_at = models.DateTimeField(auto_now=True)
    creator = models.ForeignKey(User, null=True, blank=True)
    score = models.ForeignKey('Score', blank=True, null=True)
    points = models.ManyToManyField('Points')


class Score(models.Model):
    value = models.IntegerField()
    created_at = models.DateTimeField(auto_now_add=True)
    creator = models.ForeignKey(User, null=True, blank=True)


class Points(models.Model):
    value = models.DecimalField(max_digits=3, decimal_places=1)
    caption = models.CharField(max_length=20, default='')
    created_at = models.DateTimeField(auto_now_add=True)
    creator = models.ForeignKey(User, blank=True, null=True)

And now I somehow get an instance of a Score model (without actually knowing that this is Score model) and an instance of Points model (again, without knowing that this is Points model):

>>> type(s)
<class 'myapp.models.Score'>
>>> type(p)
<class 'myapp.models.Points'>

Now I can get access to a set of related Article instances via the following code:

>>> s.article_set
<django.db.models.fields.related.RelatedManager object at 0x10d1e8610>
>>> p.article_set
<django.db.models.fields.related.ManyRelatedManager object at 0x10d1e8850>

But this is the case where I know actual DB schema and I know that attributes are called article_set. In my case I do not know the actual DB scema. And I want to get all the RelatedManager attributes of the current model instance.

I think that it is possible to implement this via ._meta attribute but I didn’t manage to do that while trying. So I would probably need an actual working example of something like get_related_managers(self) method implementation.

  • 1 1 Answer
  • 0 Views
  • 0 Followers
  • 0
Share
  • Facebook
  • Report

Leave an answer
Cancel reply

You must login to add an answer.

Forgot Password?

Need An Account, Sign Up Here

1 Answer

  • Voted
  • Oldest
  • Recent
  • Random
  1. Editorial Team
    Editorial Team
    2026-05-26T13:42:21+00:00Added an answer on May 26, 2026 at 1:42 pm

    This seems to work for me:

    def get_related_managers(self):
        managers = []
        for related_object in self._meta.get_all_related_objects():
            managers.append(getattr(self, related_object.get_accessor_name()))
        return managers
    

    You will also have to loop through self._meta.get_all_related_many_to_many_objects() if you want many to manys as well.

    UPD: In newer django versions, _meta does not have such methods, but the same can be done with self._meta.related_objects and self._meta.many_to_many.

    • 0
    • Reply
    • Share
      Share
      • Share on Facebook
      • Share on Twitter
      • Share on LinkedIn
      • Share on WhatsApp
      • Report

Sidebar

Related Questions

Let's say I have the following models class Photo(models.Model): tags = models.ManyToManyField(Tag) class Tag(models.Model):
Let's say you have a class called Customer, which contains the following fields: UserName
Let's say on a page I have alot of this repeated: <div class=entry> <h4>Magic:</h4>
Let's say I have the following entity: public class Store { public List<Product> Products
Let say I have some code HTML code: <ul> <li> <h1>Title 1</h1> <p>Text 1</p>
Let's say that I have a set of relations that looks like this: relations
Let's say that I have classes like this: public class Parent { public int
Let's say I have a simple UserControl with no codebehind: <UserControl xmlns= .... x:Class=TrafficLight.LightControl>
Let's say I'm building a data access layer for an application. Typically I have
Let's say we have a simple function defined in a pseudo language. List<Numbers> SortNumbers(List<Numbers>

Explore

  • Home
  • Add group
  • Groups page
  • Communities
  • Questions
    • New Questions
    • Trending Questions
    • Must read Questions
    • Hot Questions
  • Polls
  • Tags
  • Badges
  • Users
  • Help
  • SEARCH

Footer

© 2021 The Archive Base. All Rights Reserved
With Love by The Archive Base

Insert/edit link

Enter the destination URL

Or link to existing content

    No search term specified. Showing recent items. Search or use up and down arrow keys to select an item.