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Home/ Questions/Q 8105351
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Editorial Team
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Editorial Team
Asked: June 6, 20262026-06-06T00:08:18+00:00 2026-06-06T00:08:18+00:00

Lets say I have a structure struct s { std::deque<Object> q; //won’t work with

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Lets say I have a structure

struct s
{
     std::deque<Object> q; //won't work  with C library
}

If the structure with std::deque is initialized using C library then it wouldn’t work.

struct s
{
     std::vector<Object> v; //would work with C library
}

However, this structure with std::vector would work with C library.
I think this is because the elements in deque are not contiguous whereas the elements in vector are contiguous. I think this might be a reason but not sure.

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-06T00:08:20+00:00Added an answer on June 6, 2026 at 12:08 am

    Neither version of S will work with a C library.
    This is because C does not have any concept of how classes are layed out (or even what is in them).

    Vector can be used with C library if you pass the address of an element. Because all the elements are in contiguous memory it looks like a normal pointer and thus any C function that takes a pointer will work.

    struct Object { /* NORAML POD Object */ };
    
    extern "C" void cFunctionCall(Object* data, size_t size);
    
    
    std::vector<Object>   v;
    // initialize v
    
    cFunctionCall(&v[0], v.size()); // This will work because all members of v
                                    // are in contiguous memory
    
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