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Home/ Questions/Q 4237704
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Editorial Team
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Editorial Team
Asked: May 21, 20262026-05-21T02:48:31+00:00 2026-05-21T02:48:31+00:00

Let’s say I have an array of random numbers in no particular order. Let’s

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Let’s say I have an array of random numbers in no particular order. Let’s say these are the ID #’s for people who ran in a marathon, and they’re added to the array in the order they finish, something like:

race1 = [8, 102, 67, 58, 91, 16, 27]
race2 = [51, 31, 7, 15, 99, 58, 22]

This is a simplified and somewhat contrived example, but I think it conveys the basic idea.

Now a couple questions:

First, how could I get the IDs that are before and after a particular entry? Let’s say I am looking at runner 58 and I want to know who finished before and after him.

race1, runner58: previous finisher=67, next finisher=91
race2, runner58: previous finisher=99, next finisher=22

Second, if I’m looking at the person who finished first or last, how can I have the “next” or “previous” loop back around the array?

race1, runner8: previous finisher=27, next finisher=102
race2, runner22: previous finisher=58, next finisher=51

Lastly, I’d like to show what position each runner finished in. Given just the array and a value in it, how can I find out what ‘ordinal’ position it is in the array? Ie:

race1: runner8=1st, runner102=2nd, runner67=3rd ... runner27=last

Thanks very much!

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-21T02:48:32+00:00Added an answer on May 21, 2026 at 2:48 am

    First & Second:

    index = race1.find_index(58)
    if !index.nil?
      puts "#{race1[index-1], #{race1[index+1] || race1[0]}"
    end
    

    Lastly:

    gem install linguistics

    then

    require 'linguistics'
    Linguistics::use( :en )
    race1.each_with_index {|runner, i| puts "runner#{runner}=#{(i+1).en.ordinal}"}
    
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