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Home/ Questions/Q 254797
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Editorial Team
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Editorial Team
Asked: May 11, 20262026-05-11T21:52:38+00:00 2026-05-11T21:52:38+00:00

Let’s say I have an NSArray of NSDictionaries that is 10 elements long. I

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Let’s say I have an NSArray of NSDictionaries that is 10 elements long. I want to create a second NSArray with the values for a single key on each dictionary. The best way I can figure to do this is:

    NSMutableArray *nameArray = [[NSMutableArray alloc] initWithCapacity:[array count]];
    for (NSDictionary *p in array) {
        [nameArray addObject:[p objectForKey:@"name"]];
    }
    self.my_new_array = array;
    [array release];
    [nameArray release];
}

But in theory, I should be able to get away with not using a mutable array and using a counter in conjunction with [nameArray addObjectAtIndex:count], because the new list should be exactly as long as the old list. Please note that I am NOT trying to filter for a subset of the original array, but make a new array with exactly the same number of elements, just with values dredged up from the some arbitrary attribute of each element in the array.

In python one could solve this problem like this:

new_list = [p['name'] for p in old_list]

or if you were a masochist, like this:

new_list = map(lambda p: p['name'], old_list)

Having to be slightly more explicit in objective-c makes me wonder if there is an accepted common way of handling these situations.

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  1. Editorial Team
    Editorial Team
    2026-05-11T21:52:38+00:00Added an answer on May 11, 2026 at 9:52 pm

    In this particular case Cocoa is not outdone in succinctness 🙂

    NSArray *newArray = [array valueForKey:@"name"];
    

    From the NSArray documentation:

    valueForKey:

    Returns an array containing the
    results of invoking valueForKey: using
    key on each of the receiver’s objects.

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