Sign Up to our social questions and Answers Engine to ask questions, answer people’s questions, and connect with other people.
Login to our social questions & Answers Engine to ask questions answer people’s questions & connect with other people.
Lost your password? Please enter your email address. You will receive a link and will create a new password via email.
Please briefly explain why you feel this question should be reported.
Please briefly explain why you feel this answer should be reported.
Please briefly explain why you feel this user should be reported.
Let’s say I have ClasseA implements I, how do I do something like:
public class Classe<T> {
void function(Class<T> param) {
...
}
}
Classe<I> c=new Classe();
c.function(ClasseA.class);
Since ClasseA implements the interface I, I would like function to accept either a class literal of type ClasseA or a class implementing I.
You can specify constraints on the type this way:
Classe<T extends I>