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Home/ Questions/Q 8046599
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Editorial Team
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Editorial Team
Asked: June 5, 20262026-06-05T05:50:15+00:00 2026-06-05T05:50:15+00:00

Let’s say i have created the file String path = application.getRealPath(userSearchFolder); String name =

  • 0

Let’s say i have created the file

String path = application.getRealPath("userSearchFolder");
String name = path + "/" + (String) session.getAttribute("username") + ".xml";
File file = new File(name);

And later I want to make it available as a link, for example

 <a href"<%=file.toURI()%>">File</a>

What happens is I get the directory path not url path ->

file:/D:/Documents/NetBeansProjects/2012/GATE_Project/build/web/userSearchFolder/mjoraid.txt.xml

And when it reaches Firefox, I hover over the link and what i see is

file:///D:/Documents/NetBeansProjects/2012/GATE_Project/build/web/userSearchFolder/mjoraid.xml

When I right click and choose Copy link Location and paste it in URL the xml file opens, but when I click the link, nothing happens.

How could I get a link like this

http://localhost:8080/GATE_Project/somepage/somepage/mjoraid.xml
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  1. Editorial Team
    Editorial Team
    2026-06-05T05:50:17+00:00Added an answer on June 5, 2026 at 5:50 am

    Ok, i did it manually, similar to how i used to do it in php, create a variable that contains the website main directory.

      String searchFolderURL = "http://localhost:8080/GATE_Project/userSearchFolder/"; 
    

    and then

     <a href="<%=searchFolderURL + file.getName()%>" target="_blank"  >See original txt File </a>
    

    Thanks btw.

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